Question

In problem 10.9, if 15.0 cm of water and spirit each are further poured into the respective arms of the tube, what is the difference in the levels of mercury in the two arms? (Specific gravity of mercury = 13.6)

Answer 1

Height of water( h1) = 10+15=25cm
Height of spirit ( h2) = 12.5+15=27.5 cm
density of spirit (ds) =0.8 g/cm³
Density of Mercury (dm) = 13.6 g/cm³

Let in equilibrium the difference in level of mercury in both arms be H cm .

so, H.dm.g = h1.dw.g - h2.ds.g
H = { h1.dw - h2.ds}/dm
= { 25×1 - 27.5 × 0.8}/13.6
= 0.221 cm
Therefore mercury will rise in the arm containg spirit by 0.221 cm

Answer 2

this is the answer to your question