ABCD is a cyclic train quadrilateral in which angle is equal to 105 degree and Angle B equal to 80 degree find angle C and angle d
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Given
ABCD is cyclic quadrilateral
Angle A =105°
Angle B =80°
Find = Angle C and D
If ABCDis a cyclic quadrilateral
So, angle A +angle C = 180
(Opposite sides of cyclic quadrilateral is equal to 180°)
105+angle C =180°
Angle C = 180° - 105°
Angle C= 75°
Similarly we find Angle D
Angle B+ angle D =180°
80 + angle D = 180°
Angle D = 180° - 80°
Angle D = 100°
ABCD is cyclic quadrilateral
Angle A =105°
Angle B =80°
Find = Angle C and D
If ABCDis a cyclic quadrilateral
So, angle A +angle C = 180
(Opposite sides of cyclic quadrilateral is equal to 180°)
105+angle C =180°
Angle C = 180° - 105°
Angle C= 75°
Similarly we find Angle D
Angle B+ angle D =180°
80 + angle D = 180°
Angle D = 180° - 80°
Angle D = 100°
mala16:
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