ABCD is a diameter of a circle of radius 6 cm. The lengths
AB, BC and CD are equal. Semicircles are drawn on AB and
BD as diameters as shown in the given figure. Find the area
of the shaded region.
Answers
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Answer:
12πcm^2
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Asked on December 26, 2019 by
Mishal Castelino
ABCD is diameter of a circle of radius 6cm such that AB=BC=CD. Semicircles are drawn on AB and BD as diameter, as shown in the given figure. Find the area of the shaded region.
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ANSWER
Since, Length of AB, BC and CD are equal.
Radius of circle =6cm
Now, AD=2×6=12cm
⇒AB+BC+CD=12
⇒3AB=12
⇒AB=
3
12
⇒AB=4cm
⇒AB=BC=CD=4cm
Radius of semicircle AB=2cm
Radius of semicircle BC=4cm
Radius of semicircle AD=6cm
Area of the shaded region = Area of semicircle (AB+AD) − Area of semicircle (BD)
⇒ Area of shaded region =0.5π(2
2
+6
2
)−0.5π(4)
2
⇒ Area of shaded region =0.6π(4+36)−0.5π×16
⇒ Area of shaded region =20π−8π
⇒ Area of shaded region =12πcm^2
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