ABCD is a IIgm. X is the mid-point of AB and Y is the mid point of CD. show that AYCX is a IIgm and find the ratio ar(AXCY) : ar(ABCD)
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We know that ABCD is a parallelogram so,
AB||CD nd DA||CB
X nd Y are respectively the midpoints of the sides AB nd CD
so,
AB||CD nd 1/2AB|| 1/2CD
AX||YX
nd CY||AX
Hence AXCY is a parallelogram
Hence proved......
AB||CD nd DA||CB
X nd Y are respectively the midpoints of the sides AB nd CD
so,
AB||CD nd 1/2AB|| 1/2CD
AX||YX
nd CY||AX
Hence AXCY is a parallelogram
Hence proved......
dimple24:
Nd where the ratio is 1:2 bcz the the //ogm AXCY is half to the //ogm ABCD
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