Question

ABCD is a kite and angle A = angle C. If angle CAD = 70, angle CBD = 65, find
a) angle BCD
b) angle ADC​

Answer 1

Answer:

Step-by-step explanation:

It is given that ABCD is a kite in which ∠CAD=70°, ∠CBD=65° and ∠A=∠C.

Now, in ΔACD, we have

∠A+∠C+∠D=180° (Angle sum property)

⇒∠CAD+∠ADC+∠ACD=180°

⇒70°+70°+∠ADC=180°

⇒∠ADC=40°

Now, From ABCD, we have

∠A+∠B+∠C+∠D=360° (Sum of all the angles of quadrilateral is 360°)

⇒∠BAD+∠ABC+∠BCD+∠CDA=360°

⇒2(∠CAD)+2(∠CBD)+∠BCD+∠CDA=360°

⇒2(70)+2(65)+∠BCD+40=360°

⇒∠BCD=50°

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Answer 2

Step-by-step explanation:

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