Question

ABCD is a parallelogram. AE is
perpendicular to DC and CF is
perpendicular to AD. If AB = 12 cms,
AE = 8 cms and CF = 16 cms then
show that AD = 6 cms.
​

Answer 1

in the parallelogram ABCD

AB×AE=12×8=96

SIMILARLY....

AD×FC = X×16

NOW...

96 = 16X

X= 96\16 = 6

hence prooved

Answer 2

Question :-

In figure, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD.

Answer :-

We have, AE ⊥ DC and AB = 16 cm

∵ AB = CD [Opposite sides of parallelogram]

∴ CD = 16 cm

Now, area of parallelogram ABCD = CD x AE

= (16 x 8) cm2 = 128 cm2 [∵ AE = 8 cm]

Since, CF ⊥ AD

∴ Area of parallelogram ABCD = AD x CF

⇒ AD x CF = 128 cm

⇒ AD x 10 cm = 128 cm2 [∵ CF= 10 cm]

⇒ AD = 128/10 cm = 12.8 cm 10

Thus, the required length of AD is 12.8 cm

Hope it helps ❤ Mrk as brainliest