Question

ABCD is a parallelogram and AF bisects Angle A and CE bisects angle C

Answer 1

Answer:

Step-by-step explanation:

to prove: <FAB=<CEB

proof: <A=<C (opp sides of a parallelogram are equal)

1/2<A=1/2<C

ie <FAB=<ECF.........1

now AB is parallel to DC (opp sides are parallel)

<CEB=<ECF (Alternate interior angles).......2

from results 1 and 2,

<FAB=<CEB

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Answer 2

Here is you answer

to prove: <FAB=<CEB

proof: <A=<C (opp sides of a parallelogram are equal)

1/2<A=1/2<C

ie <FAB=<ECF.........1

now AB is parallel to DC (opp sides are parallel)

<CEB=<ECF (Alternate interior angles).......2

from results 1 and 2,

<FAB=<CEB