ABCD is a parallelogram and E is the mid point of BC. DE and AB when produced meet at F. then AF
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Answered by
1
Step-by-step explanation:
it gives us similar triangles and AF is equal to 2 BF
Answered by
1
Answer:
2AB
Step-by-step explanation:
In ||gm ABCD, E is mid-point of BC DE and AB are produced to meet at F
∵ E is mid point of BC
∴ BE = EC
In ∆BEF and ∆CDE
BE = EC
∠BEF = ∠CED (Vertically opposite angle)
and ∠EBF = ∠ECD (Alternate angles)
∴ ∆BEF ≅ ∆CDE (ASA criterian)
∴ DC = BF
But DC = AB
∴ AB = BF
AF = AB + BF = AB + AB
= 2AB
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