Abcd is a parallelogram and e is the mid point of bc.If ab =4.2cm then bl=?
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Given, E is mid point of AD
Also EB∥DF
⇒ B is mid point of AF [mid--point theorem]
so, AF=2AB (1)
Since, ABCD is a parallelogram,
CD=AB
⇒AF=2CD
AD∥BC⇒LB∥AD
In ΔFDA
⇒LB∥AD
⇒
LD
LF
=
AB
FB
=1 from (1)
⇒LF=LD
so, DF=2DL In the given figure, ABCD is parallelogram and E is the mid-point of AD. A line through D, drawn parallel to EB, meets AB produced at F and BC at L.
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