Question

abcd is a parallelogram and o is the point of intersection of its diagonal if area of triangle AOD = 4 cm 2, find the area of ABCD

Answer 1

the diagonals of the llgm divide it into four triangles area of ∆ AOB= area of ∆ COD= area of ∆ AOD = area of ∆ BOC = 4cm square meter
area of llgm ABCD = 4+4+4+4=16cm square meter