ABCD is a parallelogram angle.ADB = 28° and angle.DBC= 4Y find Y
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As, AB parallel to CD and CD is a transversal..
we have___
ADB + DBC = 180° ( sum OF co. interior angles)
28 +4y =180
4y =180-28
y =152/4 =33°
hence, y= 33°
we have___
ADB + DBC = 180° ( sum OF co. interior angles)
28 +4y =180
4y =180-28
y =152/4 =33°
hence, y= 33°
bhargavkumar1:
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