ABCD is a parallelogram. AP and CQ are perpendiculars drawn from vertices A and C respectively on diagonal BD then show that AP=CQ.
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Given: ABCD is a parallelogram
= AB = CD
∴ Consider, ΔADB and ΔCQD
= <APB = <CQD = 90
= <APB = <CPQ (Alternate Angles)
∴ By SAS Congruence rule,
= ΔAPB ≅ ΔCQD (CPCT)
= AP = CQ (CPCT)
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