ABCD is a parallelogram. AP is the height of the parallelogram from A on CD and AQ from A to BD. If AB = 6 cm, AC = 4 cm and AP = 3.2 cm, find the length of AQ.
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Given AB=8cm;BC=4cm
Distance from AB and BC is 3cm
Area of quadrilateral is given as base×height
8×3=24cm
2
Area is 24cm
2
Area of quadrilateral is given by base×height
24=4×height
Height=6cm
So the perpendicular distance is given by 6cm
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