Question

ABCD is a parallelogram bisect angle C and a 5 states angle A each of the following if the statement is true give a reason for the same
1) Angle A = Angle C
2)Angle FAB = 1/2 Angle A
3)Angle DCE = 1/2 Angle C
4)Angle FAB =Angle DCE
5)Angle DCE = Angle CEB
6)Angle CEB = Angle FAB
7)CE ||AF
8)AE ||FC​

Answer 1

Answer:

In Exercise 17.1 of Chapter 17, we shall discuss problems based on various types of quadrilaterals like – trapezium, isosceles trapezium, parallelogram, rhombus, rectangle, square. In this exercise, we mainly study the properties of a parallelogram. Students who find difficulty in understanding the concepts can refer to RD Sharma Solutions which is prepared by our expert tutors with utmost care, which helps students gain competence on the concept. Ultimately the main aim is to help students boost their confidence level and achieve high marks in their exams. Pdf can be downloaded easily from the links given below.

Answer 2

Answer:

(i) ∠A = ∠C True, Since ∠A =∠C = 55° [opposite angles are equal in a parallelogram] (ii) ∠FAB = ½ ∠A True, Since AF is the angle bisector of ∠A. (iii) ∠DCE= ½ ∠C True, Since CE is the angle bisector of angle ∠C. (iv) ∠CEB= ∠FAB True, Since ∠DCE = ∠FAB (opposite angles are equal in a parallelogram). ∠CEB = ∠DCE (alternate angles) ½ ∠C = ½ ∠A [AF and CE are angle bisectors] (v) CE || AF True, since one pair of opposite angles are equal, therefore quad. AEFC is a parallelogram

Sorry rest I don't know

Step-by-step explanation:

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