Math, asked by intelegence3707, 10 months ago

ABCD is a parallelogram circumcentring a circle. Prove that ABCD is a Rhombus

Answers

Answered by niveshsanjaygarg

Step-by-step explanation:

Given ABCD is a ||gm such that its sides touch a circle with centre O. We know that, tangents to a circle from an exterior point are equal in length. Hence, ABCD is a rhombus.

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