Question

ABCD is a parallelogram.e and f are points on opposite sides ad and bc respectively such that ed =1/3ad and bf=1/3bc.if angle adf =60 degree then find angle angle bfd.

Answer 1

Answer:

Step-by-step explanation:

as AD is parallel to BC

EDF = DFC =60

DFC+DFB =180(ASP)

So,180-DFC=BFD

180-60==BFD

120=BFD

EBF=60(ASP)

120+60+60+BED=360

BED=360-240

BED=120

Answer 2

Answer:

∠BFD = 120°

Step-by-step explanation:

Explanation:

Given, ABCD ia a parallelogram in which E and F are the points

on opposite sides  AD and BC respectively.

ED = $\frac{1}{3}$ AD

BF = $\frac{1}{3}$ BC .

and the ∠ADF = 60°

then, ∠BFD =?.

Step 1:

We have ABCD is a parallelogram

∴AD || BC    (opposite side of a parallelogram are always parallel)

⇒AD || BF

DF is a transversal .

Step 2:

∴ ∠ADF +∠BFD = 180°............(I)  (Sum of co-interior angle are 180°)

⇒∠BFD = 180° - ∠ADF .................(II)

put the value of ∠ADF  in the equation (II)

(where as ∠ADF is 60°given in th question)

So ,

∠BFD = 180° - 60°

⇒∠BFD = 120°

Final answer :

Hence , the angle of a given parallelogram ∠BFD  is 120.°