Question

ABCD is a parallelogram E is the mid-point of AB and F is the mid-point of CD. GH is any line that intersects AD,EF AND BC in G,P,H respectively. Prove that GP=PH.

Answer 1

Step-by-step explanation:

I really don't what rules does ur question follow but I can prove it using concept of Congruence triangles.

Jion GF and EH

In 2 triangles GFP and EHP

angle P = angle P(vertically opposite angles)

LG=LH(alternate angles)

LF=LE( alternate angles)

GFP~=EHP

GP=HP(CPCT).

Hope helps u .

Thank u!