Question

ABCD is a parallelogram Eis the midpoint of side BC,DE and AB when produced meets at F Prove that AF=2AB

Answer 1

Answer:

TAKE THESE TWO TRIANGLES DCE AND BEF. WE HAVE TO PROVE THESE TWO TRIANGLES CONGRUENT . SO EC = EB ( AS E IS THE MID PNT)

ANGLE BEF = DEC ( VERTICALLY OPPOSITE ANGLES)

ANGLE EBF= DCE ( DC IS PARALLEL TO AF AND ALTERNATE INTERIOR ANGLES). *

SO BY ASA CONGRUENCE RULE TRIANGLE DCE AND BEF ARE CONGRUENT.

BY C.P.C.T BF = DC. - 1

DC = AB ( ABCD IS A PARALLELOGRAM) - 2

SO AF = AB PLUS BF.

SO FROM 1 AND 2 WE GET AF = 2AB

HENCE PROVED .

Step-by-step explanation: