ABCD is a parallelogram find x
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Answer:
Given:
∠DAB = (5x + 20)°
∠BCE = (5x + 10)°
Solution:
In parallelogram ABCD,
∠DAB = ∠DCB (Opposite angles in a
∠ADC = ∠CBA parallelogram are equal)
∠DAB = ∠DCB = (5x + 20)°
Now,
∠DCB + ∠BCE = 180° (Linear pair)
(5x + 20)° + (5x + 10)° = 180°
5x + 20° + 5x + 10° = 180°
10x + 30° = 180°
10x = 180° - 30°
10x = 150°
x = 150°/10
x = 15
Therefore, the value of x is 15.
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