ABCD is a parallelogram.if angle A is equal to 65 digree,find angle B+D
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Answered by
64
Angle C = 65 degree
Therefore angle B+angle D =360- angle a + angle C
=360 - 130
=230 degrees
Therefore angle B+angle D =360- angle a + angle C
=360 - 130
=230 degrees
Answered by
3
Answer:
angle ∠B + ∠D = 230°
Step-by-step explanation:
Given ABCD is a parallelogram
and ∠A = 65°
In a parallelogram opposite angles are equal
⇒ ∠A = 65° then the opposite angle ∠C = 65°
⇒ ∠B and the opposite angle ∠D are equal
therefore the angles of the parallelogram are
∠A=65°, ∠C = 65° and ∠B, ∠D
we know that the sum of the interior angles of a quadrilateral = 360°
⇒ ∠A + ∠B + ∠C + ∠D = 65° + ∠B + 65° + ∠D = 360°
= 130° + ∠B + ∠D = 360°
= ∠B + ∠D = 230°
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