ABCD is a parallelogram.If angle CAB=32 degree and angle ABC=110 degree,calculate angle x,angle y,angle z?
(I think that x would be 180°-32° as they are AIA) am I right?
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a) To Find value of Z
= (Z + 32) + 110 = 180 [ sum of adjacent angles of a parralellogram is 180 ]
= Therefore Z = 180 - 142 = 38 Degree
b) To Find Value of Y
= Angle DAB + Angle Y = 180 Degree
[ sum of adjacent angles of a parralellogram is 180 ]
= (Z + 32) + Y = 180
= 38 + 32 + Y = 180
= Y = 110
c) To Find Value of X
Angle BAC = Angle DCA { Vertically Opposite Angles in a parallel line
32 = X Bcoz Opposite Sides of a Paralleogram are
Parallel }
Therefore X= 32, Y= 110 and Z=38 Degree
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no me solution ask me right solution okay
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