Question

ABCD is a parallelogram in which A =110. find the measure of each of the angles B C D

Answer 1

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ⓐⓝⓢⓦⓔⓡ


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Angle A = Angle C ( Opposite angles of a parralelogram are equal )


So, Angle A and Angle C = 110°


Now , Angle A + Angle B = 180° ( Consecutive angles of a parralelogram measures 180°


So, Angle A + Angle B = 180°

110° + Angle B =180°

Angle B = 180-110=70°


Now , Angle B = Angle D = 70°


So, the four angles are 110° , 70° , 110° , 70°


$hope \: it \: helps$



$<marquee > prabhudutt$

Answer 2

Answer:

It is given that ABCD is a parallelogram in which ∠A =110°.

Sum of the adjacent angles of a parallelogram is 180°.

∴ ∠A ∠B =180°

⇨ 110° ∠B =180°

⇨ ∠B =180° —110°

⇨ ∠B =70°

Also ∠B ∠C =180°

⇨ 70° ∠C =180°

⇨ ∠C =180° — 70°

⇨ ∠C =110°

Further ∠C ∠D =180°

⇨ 110° ∠D =180°

⇨ ∠D =180° —110°

⇨ ∠D =70°

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