Question

ABCD is a parallelogram in which angle d a b is equal to 75 degree and Angle DBC is equal to 60 degree calculate the measure of angle C D B and angle ADB .

Answer 1

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Answer 2

∠CDB = 45° and  ∠ADB = 60°

Step-by-step explanation:

Given:      

It is given ∠DAB = 75° and ∠DBC = 60  

Since adjacent angles of a parallelogram are supplementary

Therefore, in ΔDBC,

∠DBC + ∠BCD + ∠CDB = 180°

⇒ 60° + 75° + ∠CDB = 180°          [∠DAB = ∠BCD, opposite angle of // gm are equal]

⇒ ∠CDB = 180° - 60° -75°

⇒ ∠CDB = 45°

Now, AB parallel to CD, BD is the transversal

Therefore,

∠ADB =  ∠DBC = 60°         (Alternate Interior Angles)