Question

ABCD is a parallelogram in which in which angle dab is equal to 70 degree and Angle c and BD is equal to 45 degree find angle cdb and angle ADB

Answer 1

Answer:

Step-by-step explanation:

∠A + ∠B = 180°

⇒ 70° + ∠B = 180°

⇒ ∠B = 110°  

⇒  ∠ABD + ∠DBC = 110°  

⇒ ∠ABD + 65° = 110°

⇒ ∠ABD  = 45°

Now, ∠CDB = ∠ABD = 45°