ABCD is a parallelogram in which P Q R and S are midpoints of side ab BC CA and ad respectively prove that pqrs is a rhombus
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in the Parallelogram ABCD
AP=BP.
DR=CR.
DS=AS.
BQ=CQ.
=Now add all :-
=AP+DR+DS+BQ=BP+CR+AS+CQ.
=Now take common the similar Sides :-
=(AP+BP)(DR+CR)=(AS+DS)(BQ+CQ)
=Now cut the same sides :-
=AB+DR=AD+BC.
=Now we have : 2AB=2BC.
=We know that in a Parallelogram opposite sides are equal so :
=AB=DC=DA=CB.[opposite sides are equal]
=Hence the Given Parallelogram is a rhombus .
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