ABCD is a parallelogram in which people is the midpoint of DC and Q is a point on AC such that CQ = 1/4 AC .if PQ produced meets BC at R , PROVE THAT R IS THE MIDPOINT OF BC.
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Question :
ABCD is a parallelogram in which P is the midpoint of DC and Q is point on AC such that CQ = 1/4AC .If PQ produced meets BC at R, prove that R is the midpoint of BC.
Given :
P is the midpoint of DC
CQ = 1/4 AC
To prove :
R is the midpoint of BC
Construction :
Join BD, suppose it meets AC at S .
Proof :
∵ AO = OC = 1/2 AC
Now, CQ = 1/4 AC
= 1/4(2*OC)
= OC/2
Q is the midpoint of CO.
In ∆CDO,
∵ P is the midpoint of DC and Q is the midpoint of CO
∴ PR parallel DB and QR parallel OB
Now, in ∆COB,
∵ Q is the midpoint of CO and QR parallel OB
∴ R is the midpoint of BC
[ By converse of Midpoint theorem ]
Hence proved.
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