Abcd is a parallelogram show that 2dc vector minus bd vector equal to ac vector
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let AB = a = DC
BC = b = AD
AC, DB be the diagonals {a,b are vectors}
AC+DB
(AB+BC)+ (DA+DC)
(a+b)+ (-b+a) {-b as the direction is negative}
2a
=2DC
Hence, 2DC=AC+DB
2DC-DB = AC
BC = b = AD
AC, DB be the diagonals {a,b are vectors}
AC+DB
(AB+BC)+ (DA+DC)
(a+b)+ (-b+a) {-b as the direction is negative}
2a
=2DC
Hence, 2DC=AC+DB
2DC-DB = AC
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