ABCD is a parallelogram such that A=(3x - 10), C= (x + 80)°and D = (y + 25)°. Find
the values of x and y.
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Since ABCD is a parallelogram, AB∥DC and AD∥BC
Now, AB∥DC and transversal BD intersects them.
∴∠ABD=∠BDC since alternate angles are equal.
⇒10x=60
∘
⇒x=
10
60
∘
=6
∘
And, AD∥BC and transversal BD intersects them.
∴∠DBC=∠ADB
⇒4y=28
∘
⇒y=
4
28
∘
=7
∘
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