ABCD is a parallelogram such that ∠BAD = 120o and AC bisects ∠BAD show that ABCD is a rhombus. Please answer by question as soon as possible as I have to submit it now. I will surely mark you the brainliest/
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Answer:
yes it is possible,
Step-by-step explanation:
first draw diagram
my diagram is at the bottom of the problem
as it is parallelogram , the angle opposite to <BAD is 120 degrees
to prove that it is a rhombus we have to prove that all sides are equal
not angles
so,
we know that ac bisects <BAD
so <DAC = <CAB = 60 degrees
similarly <BCA and <DCA are 60 degrees
we can see that <CAB and <BCA are = to 60 degrees
so we can conclude that AB = BC
and BC = AD (opp sides of parallelogram are equal)
so we can conclude that AB=BC=CD=AD
thus ABCD is a rhombus
Mark as brainliest if you are satisfied with my answer
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