Question

ABCD is a parallelogram the diagonals AC and BD intersect each other at O prove that area of triangle a body is equal to area of triangle BOC

Answer 1

in triangle abc and triangle boc
AD=BC(OPP.SIDES)
AO=OC
OD=OB(DIAGONALS BISECTS EACH OTHER)
SO THAT
∆ABC =~ ∆BOC
SO THAT THERE AREAS R EQUAL

Answer 2

Answer:

Step-by-step explanation:

In triangle AOD,BOC

We have OD=OB

OA=OC

Angle AOD=BOC

triangle AOD=~BOC

(Since SAS congruent)

ar(triangle AOD)=ar(triangle BOC) H/P