ABCD is a rectangle with AB=12cm and BC=5cm Find AC
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In triangle ABC
=> AB=12cm , BC=5cm , AC =?
So, by Pythagoras theorem
=> (AC)²= (AB)² + (BC)²
=> (AC)² = (12)² + (5)²
=> (AC)² = 144 + 25
=> (AC)² = 169
=> AC = √169
=> AC= 13cm
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=> AB=12cm , BC=5cm , AC =?
So, by Pythagoras theorem
=> (AC)²= (AB)² + (BC)²
=> (AC)² = (12)² + (5)²
=> (AC)² = 144 + 25
=> (AC)² = 169
=> AC = √169
=> AC= 13cm
hope it helps uhh!!
and wish you a very...
(belated)
♡ HAPPY ♡
NEW YEAR
2019
/\_ヘ/ヽ
/ (_ (⌒厂ヽ
| \ノ
土 ● o ● 土
乂____ 乂
/ \y/ヽ
| ̄|)(| ̄ |
(_ノ_ヽ_)
(Y)(Y)
 ̄  ̄
vasanthiv78:
Ok now Please answer my second question
Answered by
30
Answer:
ABCD is Rect.
AB = 12cm
BC = 5cm
All angles of rect. are 90
Angle a'b'c'd =90
In triangle ABC
H²=B²+P²
AC²= 12²+ 5²
AC² = 144 + 25
AC² = 169
AC = √169
AC = 13
Step-by-step explanation:
hope it is use full
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