ABCD is a parallelogram then find the values of x and y angle A(3x-10) angle B is(2y+55) angleC is (y+80) and angle D is (x+25)
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In a parallelogram: angles A = C So 3x - 10 = y + 80
3x - y = 90 --- (1)
Also, angles B = D So 2 y + 55 = x + 25
x - 2 y = 30 -- (2)
Solve the two equations 3 * (2) - (1) to get:
y = 0, x = 30
So A = C = 80, B = D = 55
But in a parallelogram: A + B = C + D = 180 deg
So there is some mistake in the given problem. you cannot get x and y so that given angles are those of a parallelogram.
3x - y = 90 --- (1)
Also, angles B = D So 2 y + 55 = x + 25
x - 2 y = 30 -- (2)
Solve the two equations 3 * (2) - (1) to get:
y = 0, x = 30
So A = C = 80, B = D = 55
But in a parallelogram: A + B = C + D = 180 deg
So there is some mistake in the given problem. you cannot get x and y so that given angles are those of a parallelogram.
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Step-by-step explanation:
ya I also solved this question but I think there is a problem in question
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