Math, asked by sovi1, 1 year ago

ABCD is a parallelogram then find the values of x and y angle A(3x-10) angle B is(2y+55) angleC is (y+80) and angle D is (x+25)

Answers

Answered by kvnmurty
6
In a parallelogram:   angles A = C    So  3x - 10 = y + 80
      3x - y = 90      --- (1) 
  Also,   angles  B = D     So  2 y + 55 = x + 25
       x - 2 y = 30     -- (2)
Solve the two equations 3 * (2) - (1)  to get:
       y = 0,  x = 30

So   A = C = 80,  B = D = 55
But in a parallelogram:   A + B = C + D = 180 deg

So there is some mistake in the given problem.   you cannot get x and y so that given angles are those of a parallelogram.
Answered by dhannirankarji71
3

Step-by-step explanation:

ya I also solved this question but I think there is a problem in question

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