Question

Abcd is a parallelogram then prove that area triangle abc is equal to area triangle abc d is equal to area triangle abc is equal to area triangle a cd is equal to half a parallelogram abcd

Answer 1

Answer:after draw a parallelogram ABCD with a diagonal AC

Step-by-step explanation:

Given-ABCD is a parallelogram

To prove- area of triangle ABC=area of triangle ADE=1/2area of ABCD

Proof:

In triangle ABC and CDA

AB=CD. ( OPP sides of parallelogram)

BC=DA. (OPP sides of parallelogram)

AC=CA. (common)

Therefore both triangles are congruent by SSS axiom

Hence ar(ABC)=ar(CDA)

Now,

ar(ABC)+ar(CDA)=ar(ABCD)

2ar(ABC)=ar(ABCD)

arABC=1/2ar(ABCD) proved

Answer 2

Answer:

If the triangles ABC and

Step-by-step explanation:

is if the Triangles ABC and DSE are equal in the area the area of the triangle ABC if the Triangles ABC and DBC are quality in area the area of the triangle ABC