Question

ABCD is a parallelogram where AB || CD.E is a point on CD. if the area of ∆ A B E = 14.2 CM square, find the area of the parallelogram ABCD. support your answer with a proper reason

Answer 1

Hi there!
Area of parallelogram ABCD= Base × Height
Area of triangle ABE=1/2×Base × Height
As you can see base and height are common in both, as in the figure,
Area of parallelogram ABCD = 2× Area of triangle ABE
= 14.2 cm^2 ×2
=28.4 cm^2
Hope this helps.....

Answer 2

Given: AB || CD, triangle ABE = 14.2 cm^2

To find: the area of the parallelogram ABCD

Solution:

• Since we have given that AB is parallel to CD,

• So, we have the formula for area of parallelogram                                      

                    Area of parallelogram ABCD= Base × Height

• Now we know that,

                    Area of triangle ABE=1/2×Base × Height

• We can conclude that base and height on both, parallelogram and triangle are same so

                    Area of parallelogram ABCD = 2 (Area of triangle ABE)

                    = 14.2 cm^2 ×2

                    =28.4 cm^2

Answer:

•   So, the area of the parallelogram ABCD = 28.4 cm^2