Question

ABCD is a parallelogram whose diagonals AC and BD meet at o m and n are the midpoints of Ab and CD respectively prove that AMC is a parallelogram whose area is half that of ABCD

Answer 1

In AMCN,

am is parallel to cn

am = cn ; as ab = cd   so half ab = half cd

hence if in a quad one pair of opp sides is equal and parallel then it is a parallelogram

so AMCN is a parallelogram

Answer 2

Step-by-step explanation:

here is your answer bro ok with a few questions about this one