Question

ABCD is a parallelogram whose diagonals intersect at O. If AO = 16, OC = x+y, OB = y + 7 and OD =

20, find x and y​

Answer 1

Step-by-step explanation:

Given : AO = 16 , OC = x + y , OB = y + 7 , OD = 20

As we know that,

Diagonals of parallelogram bisects each other

then,

AO = OC and OB = OD

Now,

OB = OD

y + 7 = 20

y = 20 - 7

y = 13

Again,

AO = OC

16 = x + y

16 = x + 13

16 - 13 = x

x = 3

Hence, x = 3 and y = 13

Answer 2

Answer:

Step-by-step explanation:

given that :

AO=16, OC=x+y ,OB=y+7, OD=20

We need to find x and y

here we can say that

AO=OC and OB=OD

for finding y:

OB=Y+7=OD=20

SO,

Y+7=20

Y=20-7=13

We found that y is 13

now we need to find x

we earlier said that AO=OC

so we can say that

AO=16=OC=X+Y

so, x+y=16

we already found out the value of y ie. 13

so, x+13=16

x=16-13=3

therefore here x=3 and y=13

hope this helps.....please mark it as brainliest