Question

ABCD is a parallelogram whose diagonals intersect eachother at p. if the area is 56cm2., find the area of triangle APD​

Answer 1

I am assuming that point O is where the diagonals intersect. Because the diagonals of a parallelogram bisect each other all 4 triangles, while not congruent (unless your parallelogram happens to be a rhombus) are equal in area. So Triangle APD is 1/4 of 64 cm^2 which is 16 cm^2.

Answer 2

Answer:

14cm2 is your answer