Math, asked by Pjal6588, 1 year ago

Abcd is a parallelogram wirh ab 15cm bc 18cm the height of the parallelogram from vertex a to bc is 9cm find the height of the parallelogram from vertex c to ab

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Answered by Anonymous
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ABCD is a parallelogram with AB=15cm and bc=18cm.the height of a parallelogram from vertex A to BC is 9cm.find the height of parallelogram from vertex C to AB?

Ask for details Follow Report by Vjyganiger 03.01.2015

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arpit12 Beginner

AB=15

BC=18

CO IS THE PERPENDICULAR ON AB.

CO=9

So,Area of parallelogram ABCD =AB*CO

=18*9=162

162=BC*AM

AM=162/15=10.8

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birendrak1975

birendrak1975 Expert

Let the height from A to BC be AE.

LET THE HEIGHT FROM C TO AB BE CF

AB=CD=15CM (OPPOSITE SIDES OF A PARALLELOGRAM ARE EQUAL)

BC=AD=18CM ( " " " " " " " )

AE=9CM

AREA OF PARALLELOGRAM=BASE X PERPENDICULAR HEIGHT FROM BASE

AREA= (18 X 9)CM²= 162CM²

II CASE

ARE OF IIGM=BASE X PERPENDICULAR TO BASE HEIGHT

AREA= (15 X CF)CM²⇒162/15=CF

CF=10.8CM

Hope this helps you ☺️⭐✨✨⭐✌️✌️
Answered by garv1510
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hope it will help you

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