ABCD is a parallogram. P and Q are points on AD and BC. Such that AP is 1/4th of BC. Prove the BPDQ is a parellogram
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Step-by-step explanation:
- PB || DQ and PD || BA
- BP = DQ and PD = BQ
- <P = <Q ( < means angle)
- <B = <D ( < means angle)
- sum of adjacent sides 180 °
- so, hence proved BPDQ is a parallelogram
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