ABCD is a parellelogram, X and Y are points on DC and AB such that AY = CX. Prove that XY and BD bisect each other.
Answers
Answered by
6
See the diagram.
Let XY and BD intersect at O.
given that AY=CX
we know that AB= CD
so AB- AY = CD- CX
or BY=DX
In triangle, YOB and XOD,
angle YOB = angle XOD
angle ODX = angle OBY
BY=DX
So both are congruent.
Thus OD = BO
and XO = YO
So they bisect each other.(proved)
Let XY and BD intersect at O.
given that AY=CX
we know that AB= CD
so AB- AY = CD- CX
or BY=DX
In triangle, YOB and XOD,
angle YOB = angle XOD
angle ODX = angle OBY
BY=DX
So both are congruent.
Thus OD = BO
and XO = YO
So they bisect each other.(proved)
Attachments:
Answered by
4
we know that opposite sides are equal in parellelogram
AB=CD
1/2 AB=1/2 CD
let BD and XY meets at O
in triangle DOX and triangle BOY DX = by proved
angle DOX =angle BOY vertically opposite angle
angle ODX = angle OBY alternate interior angle
therefore triangle DOX is congurant to triangle BOY therefore DO = BO
therefore XY bisects BD
hence proved
AB=CD
1/2 AB=1/2 CD
let BD and XY meets at O
in triangle DOX and triangle BOY DX = by proved
angle DOX =angle BOY vertically opposite angle
angle ODX = angle OBY alternate interior angle
therefore triangle DOX is congurant to triangle BOY therefore DO = BO
therefore XY bisects BD
hence proved
Similar questions