ABCD is a quadrilateral in which AD BC and angle DAB =angleCBA prove than
1 triangle ABD =triangleBAC
2 BD =AC
3 angle ABD=BAC
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ABCD is a quadrilateral, where AD=BC and ∠DAB=∠CBA
In △ABD and △BAC,
⇒ AD=BC [ Given ]
⇒ ∠DAB=∠CBA [ Given ]
⇒ AB=BA [ Common side ]
∴ △ABD≅△BAC [ SAS Congruence rule ]
∴ ∠ABD=∠BAC [ CPCT ]
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