ABCD is a quadrilateral in which AD=BC and angle DAB= angle CBA. Prove that
∆ABD=∆BAC
BD=AC
ABD=Angle BAC
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HEY BUDDY
HERE IS THE ANSWER:
Given:
AD = BC
Angle ABD = Angle CBA
To Prove:
triangle ABD = triangle BAC
BD = AC
Angle ABD = Angle BAC
Proof
(i) In triangle ABD & triangle BAC
AB = BA (common)
Angle DAB = Angle CBA (given)
AD = BC (given)
therefore, ABD = BAC (By SAS)
(ii) triangle ABD = triangle BAC (as proved)
then, BD = AC (by CPCT)
(iii) Angle ABD = Angle BAC (by CPCT)
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