ABCD is a quadrilateral in which AD=BC and angle DAB= angle CBA. Prove that ∆ABD =~ ∆BAC.
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Answered by
26
Given,
AD=BC(given)
\_DAB=\_CBA(angle)
AB=BA(side)
By S.A.S congruency rule.
tri ABD=~triBAC.
Hope it helps...
AD=BC(given)
\_DAB=\_CBA(angle)
AB=BA(side)
By S.A.S congruency rule.
tri ABD=~triBAC.
Hope it helps...
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Answered by
13
Given,
AD=BC(given)
<DAB=<CBA(given )
AB=BA(common side)
By S.A.S congruency rule.
tri ABD=~triBAC.
Hope it helps...
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