Math, asked by vikbha12, 9 months ago

ABCD is a quadrilateral in which AD = BC and
DAB Z CBA (see Fig. 7.17). Prove that
(1) A ABD = ABAC
(ii) BD=AC
(iii) ZABD=ZBAC.
Fig. 7.17
1 parpendiculars to a line​

Answers

Answered by lokeshgadhi
19

Answer:

=> ∠ADB = ∠BCA

=> BD = AC

=> ∠ABD = ∠BAC

Step-by-step explanation:

ABCD is a quadrilateral in which AD = BC and

∠DAB = ∠ CBA

in Δ ABD & Δ ABC

AB = AB Common

AD = BC given

∠DAB = ∠ CBA given

=> Δ ABD ≅ Δ ABC

=> all Corresponding sides & Angles are equal

=> ∠ADB = ∠BCA

=> BD = AC

=> ∠ABD = ∠BAC

QED

Proved

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