ABCD is a quadrilateral in which AD = BC and
DAB Z CBA (see Fig. 7.17). Prove that
(1) A ABD = ABAC
(ii) BD=AC
(iii) ZABD=ZBAC.
Fig. 7.17
1 parpendiculars to a line
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Answer:
=> ∠ADB = ∠BCA
=> BD = AC
=> ∠ABD = ∠BAC
Step-by-step explanation:
ABCD is a quadrilateral in which AD = BC and
∠DAB = ∠ CBA
in Δ ABD & Δ ABC
AB = AB Common
AD = BC given
∠DAB = ∠ CBA given
=> Δ ABD ≅ Δ ABC
=> all Corresponding sides & Angles are equal
=> ∠ADB = ∠BCA
=> BD = AC
=> ∠ABD = ∠BAC
QED
Proved
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