Question

ABCD is a quadrilateral in which measures
of angle D and angle C are 60 degree, and 100
degree respectively. If the internal bisectors of
angle A and angle B meet at P, then measure of
angle APB is​

Answer 1

Answer:

is the answer 80°

pls tell if the answer is correct so that I can give you step by step explanation

Answer 2

Answer:

80°

Step-by-step explanation:

Since, angle A + angle B + angle C + angle D = 360°

=>(it is 'implies that' not equal to and greater than) A+B+60°+100°=360°

=>A+B+160°=360°

=>A+B=360°-160°=200°

Since, AP and BP bisect angles PAB and PBA respectively.

=>Angle PAB + Angle PBA = 1/2(angle A + angle B)

=>Angle PAB + Angle PBA = 1/2×200°=100°

Since ABP is a triangle. Therefore,

Angle PAB + Angle PBA + Angle APB = 180°

100° + Angle APB = 180°

=>Angle APB = 180°-100°=80°

Therefore, angle APB = 80°