Abcd is a quadrilateral inscribed in centre O. cd is produced to E such that angle AED=95° angle OBA=30°.find OAC
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Given,
ABCD is quadrilateral
angle AED = 95
OBA = 30
To find - angle OAC
Construction - Side CD is extended to point E
Solution -
OBA = 30 ....(Given)
therefore, OBA + OAC = 180 ....(Linear pair of angles)
30 + OAC = 180
therefore OAC = 180 - 30
OAC = 150
ABCD is quadrilateral
angle AED = 95
OBA = 30
To find - angle OAC
Construction - Side CD is extended to point E
Solution -
OBA = 30 ....(Given)
therefore, OBA + OAC = 180 ....(Linear pair of angles)
30 + OAC = 180
therefore OAC = 180 - 30
OAC = 150
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