ABCD is a quadrilateral prove that
AB + BC+CD+ DA > AC + BD
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if a b + BC + CD + a is a quadrilateral that prove the Kaun currency of AC + BD prove that AC + BD AC is equal to BD
so the answer will be a b + BC are congruent triangles
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Step-by-step explanation:
ABCD is a quadrilateral and AC, and BD are the diagonals.
Sum of the two sides of a triangle is greater than the third side.
So, considering the triangle ABC, BCD, CAD and BAD, we get
AB + BC > AC
CD + AD > AC
AB + AD > BD
BC + CD > BD
Adding all the above equations,
2(AB + BC + CA + AD) > 2(AC + BD)
⇒ 2(AB + BC + CA + AD) > 2(AC + BD)
⇒ (AB + BC + CA + AD) > (AC + BD)
HENCE, PROVED
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