Math, asked by sambeet94, 8 months ago

ABCD is a quadrilateral prove that
AB + BC+CD+ DA > AC + BD ​

Answers

Answered by neerajsingh989183804
0

Answer:

if a b + BC + CD + a is a quadrilateral that prove the Kaun currency of AC + BD prove that AC + BD AC is equal to BD

so the answer will be a b + BC are congruent triangles

Answered by ayush2005301
2

Answer:

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Step-by-step explanation:

ABCD is a quadrilateral and AC, and BD are the diagonals.

Sum of the two sides of a triangle is greater than the third side.

So, considering the triangle ABC, BCD, CAD and BAD, we get

AB + BC > AC

CD + AD > AC

AB + AD > BD

BC + CD > BD

Adding all the above equations,

2(AB + BC + CA + AD) > 2(AC + BD)

⇒ 2(AB + BC + CA + AD) > 2(AC + BD)

⇒ (AB + BC + CA + AD) > (AC + BD)

HENCE, PROVED

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