Question

ABCD is a quadrilateral with angle A = angle B, and angle C = angle D. If angle A=2angke C, find the measure of each
angle.​

Answer 1

Answer:

Given : ABCD is a quadrilateral

\begin{gathered}\angle A = \angle C...(1) \\\\\angle B = \angle D...(2) \\\\\angle A= 2\angle B ..(3)\end{gathered}

∠A=∠C...(1)

∠B=∠D...(2)

∠A=2∠B..(3)

To find : the measure of each angle

Solution:

we know that sum of all the angles of the quadrilateral is 360 degrees

thus

\angle A +\angle B + \angle C + \angle D = 360^\circ∠A+∠B+∠C+∠D=360

∘

from equation 1 ,2,and 3

2B +B +2B +B = 360

6B = 360

B = 60°

therefore

\begin{gathered}\angle B = \angle C = 60^\circ \\\\\angle A = \angle C = 2\angle B = 2\times 60 = 120^\circ\end{gathered}

∠B=∠C=60

∘

∠A=∠C=2∠B=2×60=120

∘

hence , all the angle are 60°,120°,60°,120°

Step-by-step explanation:

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Answer 2

Answer:

angle a , b = 60°

Angle c , d = 2×60 =120°

Step-by-step explanation:

ATQ

Sum of all Angle of quadrilateral is 360°

Angle A(x) = 2 Angle C

Angle A = Angle B

Angle C = Angle D

a+b+c+d = 360°

x+x+2x+2x = 360°

6x = 360°

x = 360°/6

x = 60°

so, angle a , b = 60°

Angle c , d = 2×60 =120°

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