Math, asked by StudiousDG3290, 8 months ago

Abcd is a quadrilateral with ba parallel to cd. ac and bd meet at x where x =8cm and xa=10cm.if bd=27,then find the length of bx

Answers

Answered by bhagyashreechowdhury
6

The length of BX is  15 cm.

Step-by-step explanation:

Referring to the figure attached below, we have

ABCD is a quadrilateral with BA // CD

AC and BD intersect at X

CX = 8 cm

XA = 10 cm

BD = 27 cm

Let's consider ΔBXA and ΔDXC, we have

∠BXA = ∠DXC ...... [∵BA // CD, vertically opposite angles]

∠ABX = ∠CDX ...... [∵ BA // CD, alternate angles]

By AA similarity, ΔBXA ~ ΔDXC

We know that the corresponding sides of similar triangles are proportional to each other.

BX/DX = XA/CX

⇒ BX/(BD - BX)  = XA/CX

substituting the values of BD, AX & CX

⇒ BX/(27-BX) = 10/8

⇒ 8BX = 10 (27 - BX)

⇒ 8BX = 270 - 10BX

⇒ 18BX = 270

BX = 15 cm

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