in figure AB and AC are tangents drawn from A. angle BAC is 90 degree O is centre of circle prove that quadrilateral BACO is square
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ab equals to AC because tangents on the same.
angle BAC is equal to 90 degree given Angle B and angle C is equal to 90° because tangent perpendicular to radius
ab equals to AC because radii of a same circle
angle is equal to 90 degree by angle sum property
therefore a quadrilateral with all angles is equal to 90 degree and two pairs of adjacent sides equal is a square
angle BAC is equal to 90 degree given Angle B and angle C is equal to 90° because tangent perpendicular to radius
ab equals to AC because radii of a same circle
angle is equal to 90 degree by angle sum property
therefore a quadrilateral with all angles is equal to 90 degree and two pairs of adjacent sides equal is a square
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